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I know how to do it but right now I'm cooking and have no time please say if the first part is right and the second part will be much appreciated!

I know how to do it but right now Im cooking and have no time please say if the first part is right and the second part will be much appreciated class=

Respuesta :

Part A is correct. We have x+15 as the length and x+3 as the width. Convention usually has the width be the smaller of the two.

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Part B will have you replace x with 8 and simplify

length = x+15 = 8+15 = 23

width = x+3 = 8+3 = 11

the rectangle is 23 yards by 11 yards, so the area is 23*11 = 253 square yards

bekkarmahdi702

Answer:

Below

Step-by-step explanation:

As we see the area is expressed as second degree polynomial

We have already a side wich is (x+15)

● x^2 +18x + 45 = w × (x+15)

● w = (x^2 +18x+45)/(x+15)

Using the eucledian division we get:

● w = x+3

Since x^2 +18x +45 = (x+15) × (x+3)

So your answer was right

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Let's calculate the dimensions if x= 8 yards

● the length

x+15 = 8+15 = 23 yards

● the width

x+3 = 8 + 3 = 11 yards

● the area

(x+15)×(x+3) = 23 × 11 = 253 yards^2

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