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Hi people, Please if someone can give me a hand, l already have done the first part of the exercise, but l cant make Angle CAB= X^0 c) calculate the lower bound for the value of tan X^0 there is the answer 1.02 (2dp) but l have no clue how to get it thanks i used Toa (Tan = Opp/ adj) but l couldnt find it thanks

Hi people Please if someone can give me a hand l already have done the first part of the exercise but l cant make Angle CAB X0 c calculate the lower bound for t class=
Hi people Please if someone can give me a hand l already have done the first part of the exercise but l cant make Angle CAB X0 c calculate the lower bound for t class=

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sqdancefan

Answer:

  (c) 1.02

Step-by-step explanation:

(c) The tangent is the ratio of Opposite to Adjacent. Its lowest value will be found where Opposite is lowest, and Adjacent is highest:

  min tan(A) = (min BC)/(max AB) = 75/73.5 ≈ 1.020408...(42-digit repeat)

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