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Find an equation of the line: Through the point (2, −4) with a y-intercept of −2 Through the points (4,2) and (3,1) Through the point (3,2) with a slope of −2

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Answer and Step-by-step explanation: Equations of line through points and slope can be determined by:

[tex]y-y_{0}=m(x-x_{0})[/tex]

m is slope

  • Point (2,-4) and y-intercept = -2

Y-intercept is point (0,-2)

m = [tex]\frac{y_{a}-y_{b}}{x_{a}-x_{b}}[/tex]

m = [tex]\frac{-4-(-2)}{2-0}[/tex]

m = - 1

Equation:

[tex]y+2=-1(x-0)[/tex]

[tex]y=-x-2[/tex]

  • Points (4,2) and (3,1)

m = [tex]\frac{2-1}{4-3}[/tex]

m = 1

Equation:

[tex]y-2=(x-4)[/tex]

[tex]y=x-2[/tex]

  • Point (3,2) and slope = -2

m = -2

Equation:

[tex]y-2=-2(x-3)[/tex]

[tex]y=-2x+6+2[/tex]

[tex]y=-2x+8[/tex]

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