Consider the following binomial experiment: A study in a certain community showed that 6% of the people suffer from insomnia. If there are 10,300 people in this community, what is the standard deviation of the number of people who suffer from insomnia?

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Answer:

The standard deviation is  [tex]\sigma = 24.10[/tex]

Step-by-step explanation:

From the question we are told that

     The proportion of those that suffer from insomnia is  p  =  6%  =  0.06

      The  sample size is  n =  10300

         

Generally the proportion of those that do not suffer from  insomnia is mathematically represented as

               [tex]q = 1-p[/tex]

substituting values

               [tex]q = 1 -0.06[/tex]

               [tex]q = 0.94[/tex]

Generally the standard deviation is mathematically evaluated as

         [tex]\sigma = \sqrt{n * p * q }[/tex]

substituting values

         [tex]\sigma = \sqrt{ 10300 * 0.06 * 0.94 }[/tex]

        [tex]\sigma = 24.10[/tex]

fichoh

Using the binomial probability concept, the standard deviation of the number of people who suffer from insomnia is 24.10

Recall :

  • [tex] standard \: deviation, σ = \sqrt{n \times \: p \: (1 - p)} [/tex]

  • p = probability of success = 6% = 0.06
  • 1 - p = 1 - 0.06 = 0.94
  • Sample size, n = 10300

Substituting the values into the equation :

[tex] standard \: deviation, σ = \sqrt{10300 \times \: 0.06 \: (1 - 0.06)} [/tex]

[tex] standard \: deviation, σ = \sqrt{10300 \times \: 0.06 \: 0.94} [/tex]

[tex] standard \: deviation, σ = \sqrt{580.92} = 24.10[/tex]

Hence, the standard deviation is 24.10.

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