SOMEONE PLZ HELP ME ON THIS PROBLEM!!!!! I WILL GIVE BRAINLIEST TO THE BEST ANSWER!!!!!


Answer:
D
Step-by-step explanation:
End behaviour refers to the asymptotes, which both exponential functions have the same one at y = 2. However, they have different y - intercepts. The first one has a y - intercept of 4 and the second one has a y - intercept of 6. Thus, the answer is D.
Answer:
Step-by-step explanation:
Let's name the function from graph: f
for f:
y-intercept = f(0) = 4
for x → ∞, f(x)→2
for g:
y-intercept = f(0) = 4(¹/₄)⁰+2 = 4•1+2 = 4+2 = 6 ≠4
f(1) = 4(¹/₄)¹+2 = 4•¹/₄+2 = 1+2 = 3
f(2) = 4(¹/₄)2+2 = 4•¹/₁₆+2 = ¹/₄+2 = 2¹/₄
f(3) = 4(¹/₄)³+2 = 4•¹/₆₄+2 = ¹/₁₆+2 = 2¹/₁₆
f((5) = 4(¹/₄)⁵+2 = 4•¹/₁₈₂₄+2 = ¹/₅₁₂+2 = 2¹/₅₁₂
....
so for x x → ∞, f(x)→2