Can you help Jorge organize the results into a two-way frequency table?

Answer:
See Explanation
Step-by-step explanation:
Given
Students = 24
Musical Instrument and Sport = 6
Neither = 3
Sport = 14
Required
Complete the two-way frequency table
-------------------------------------------------------- Plays sport || Does not play sport
Plays a musical instrument ---------------------6--------------------------------------
Does not play a musical instrument -------------------------------------3-----------
Total ---------------------------------------------------- 14 ---------------------------------------
To solve this, we'll make use of the following naming rules
A represent students that plays musical instrument; A = 6
B represent students that do not play musical instrument
C represent students that plays sport
D represent students that do not play sport; D = 3
Considering the first column [Plays a sport] and taking note of the naming rules;
[tex]A + B = 14[/tex]
Substitute 6 for A
[tex]6 + B = 14[/tex]
Solve for B
[tex]B = 14 - 6[/tex]
[tex]B = 8[/tex]
Also, given that there are 24 students in the class and 14 of them play sport; this implies that 10 do not play sport
Considering the second column [Does not play a sport]
[tex]C + D = 10[/tex]
Substitute 3 for D
[tex]C + 3 = 10[/tex]
Solve for C
[tex]C = 10 - 3[/tex]
[tex]C = 7[/tex]
Hence, the complete table is:
-------------------------------------------------------- Plays sport || Does not play sport
Plays a musical instrument ---------------------6--------------------------7----------
Does not play a musical instrument ---------8--------------------------3---------
Total ---------------------------------------------------- 14 -----------------------10---------