Respuesta :

Dod1T

[tex] \huge{ \bold{ \bigstar \: pythagoras \bigstar}}[/tex]

Pythagoras :

[tex] {10}^{2} = {x}^{2} + {x}^{2} [/tex]

[tex]100 = 2{x}^{2}[/tex]

[tex]100 \div 2 = {x}^{2} [/tex]

[tex]50 = {x}^{2} [/tex]

[tex]x = \sqrt{50} [/tex]

[tex]x = \sqrt{25 \times 2} [/tex]

[tex] \red{x = 5 \sqrt{2} }[/tex]

altavistard

Answer:

Step-by-step explanation:

Compare this to a similar figure with hypotenuse √2 and leg lengths all 1.

Write and solve an equation of ratios, as follows:

  x        10

------ = ------

  1        √2

              10√2

'then x = --------  =  5√2

                  2

                                       

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