trigonometry help got one right need help with another

Answer:
B. [tex] \frac{HI}{GI} [/tex]
Step-by-step explanation:
The trigonometric ratio formula for tangent of any angle in a right triangle is given as:
tan(θ) = [tex] \frac{opposite}{adjacent} [/tex]
Note: it is the length of the side opposite to the θ, and the length of the side adjacent to θ.
Thus, in the right triangle given, ∆GHI,
θ = <G
The length of side the opposite <G = HI
The length of the side adjacent to <G = GI
Therefore, the equivalent of tan(<G) = [tex] \frac{HI}{GI} [/tex]