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Each of two parents has the genotype blue/brown​, which consists of the pair of alleles that determine eye color​, and each parent contributes one of those alleles to a child. Assume that if the child has at least one blue ​allele, that color will dominate and the​ child's eye color will be blue. a. List the different possible outcomes. Assume that these outcomes are equally likely. b. What is the probability that a child of these parents will have the brown/brown ​genotype? c. What is the probability that the child will have blue eye color​?

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Oseni

Answer:

See the answer below.

Explanation:

Let the allele for eye color be represented by A. Blue is dominant over brown eye color, hence, blue allele would be A while brown eye allele would be a.

Two parents have the genotype blue/brown which is equivalent to Aa.

                   Aa    x    Aa

    AA               2Aa                aa

 blue eyes     blue eyes         brown eyes

a. Different possible outcomes: AA blue eyes, Aa blue eyes, and aa brown eyes.

b. Probability of a child from the cross having brown/brown (aa) genotype = 1/4 or 25%

c. Probability that the child would have blue eye color = 3/4 or 75%

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