Answer:
m∠A = 62°
m∠C = 28°
AC = 17 units
Step-by-step explanation:
In the given triangle ABC,
m∠B = 90°, Cos(C) = [tex]\frac{15}{17}[/tex] and AB = 16 units
Since, Cos(C) = [tex]\frac{\text{Corresponding side}}{\text{Hypotenuse}}[/tex]
Cos(C) = [tex]\frac{\text{Corresponding side}}{\text{Hypotenuse}}=\frac{15}{17}[/tex]
[tex]\text{C}=\text{Cos}^{-1}(\frac{15}{17})[/tex]
m∠C = 28.07°
m∠C ≈ 28°
Therefore, side BC = 15 units and AC = 17 units
Now we apply Sine rule in the given triangle.
Sin(A) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{\text{BC}}{\text{AC}}[/tex]
= [tex]\frac{15}{17}[/tex]
A = [tex]\text{Sin}^{-1}(\frac{15}{17} )[/tex]
A = 61.93°
m∠A = 62°
