EXTRA POINTS. WILL GIVE A BRAINLIEST AND A THANK YOU. ANSWER ASAP... I want a clear, grammatically correct answer please, Part A and Part B separate; This is an essay, please write it as such. All steps! Easy to understand! Josh and his friends bought vanilla wafers for $4 per packet and chocolate wafers for $1 per packet at a carnival. They spent a total of $45 to buy a total of 27 packets of wafers of the two varieties. Part A: Write a system of equations that can be solved to find the number of packets of vanilla wafers and the number of packets of chocolate wafers that Josh and his friends bought at the carnival. Define the variables used in the equations. (5 points) Part B: How many packets of chocolate wafers and vanilla wafers did they buy? Explain how you got the answer and why you selected a particular method to get the answer. (5 points)

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Answer:

Part A:

[tex]x+y=27 \\4x+y = 45[/tex]

Part B:

Number of vanilla wafers packets bought = 6  and

Number of chocolate wafers packets bought = 21

Step-by-step explanation:

Given:

Cost of each packet of vanilla wafer = $4

Cost of each packet of chocolate wafer = $1

Total number of packets bought = 27

Total money spent = $45

Part A:

To write a system of equations for the given situation.

Here, we do not know the number of packets bought for each type of wafer.

We just know that total number of packets bought and the total money spent in buying those packets.

Let us suppose,

Number of packets of vanilla wafers bought = [tex]x[/tex] and

Number of packets of chocolate wafers bought = [tex]y[/tex]

Total number of packets = Number of packets of vanilla wafers bought Plus Number of packets of chocolate wafers bought:

i.e. [tex]x+y=27 ...... (1)[/tex]

Money spent on vanilla wafers packets = [tex]4 \times x[/tex]

Money spent on chocolate wafers packets = [tex]1 \times y[/tex]

Total money spent = [tex]4x+y = 45 ...... (2)[/tex]

So, the system of equations is:

[tex]x+y=27 \\4x+y = 45[/tex]

Part B:

To find number of packets bought for each flavor = ?

Here, we have two equations and two variables [tex]x[/tex] and [tex]y[/tex].

As, the coefficients of [tex]y[/tex] in both the equations are same.

Let us subtract equation (1) from (2):

[tex]4x+y-x-y=45-27\\\Rightarrow 3x = 18\\\Rightarrow \bold{x =6}[/tex]

By equation (1), putting the value of [tex]x[/tex] and solving for [tex]y[/tex]:

[tex]6+y=27\\\Rightarrow \bold{y =21}[/tex]

So, number of vanilla wafers packets bought = 6  and

number of chocolate wafers packets bought = 21