Answer:
Option (1)
Step-by-step explanation:
The given triangle JKL is an equilateral triangle.
Therefore, all three sides of this triangle will be equal in measure.
Side JK = JL = KL = 48 units
Perpendicular LM drawn to the base JK bisects the base in two equal parts JM and MK.
By applying tangent rule in ΔJML,
tan(∠KJL) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]
= [tex]\frac{\text{LM}}{\text{JM}}[/tex]
= [tex]\frac{\text{LM}}{24}[/tex]
Since, Sin(K) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
Sin(60)° = [tex]\frac{\text{LM}}{48}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\text{LM}}{48}[/tex]
LM = 24√3
Now, tan(∠KJL) = [tex]\frac{\text{LM}}{24}[/tex]
= [tex]\frac{24\sqrt{3} }{24}[/tex]
Therefore, Option (1) will be the answer.
