Answer:
Step-by-step explanation:
1- on Monday the number of tricycles: 51/3=17 or 48/3=16 ( can't be 50)
2-the algebraic equation is : t=w/3 ( t=tricycle, w: wheels)
3-On Wednesday: (b for bicycle and t=tricycle)
2b+3t=61
b+t=24 ⇒ b=24-t
solve by substitution:
2(24-t)+3t=61
48-2t+3t=61
t=61-48 ⇒ t=11
solve for b=24-t
b=24-11=13
4)t: tricycles, b for bicycles, n for tandem
t+b+n=144 ( each has one handlebar)⇒ t=144-b-n
2t+2b+4n ( for the pedales)
3t+2b+2n=320 ( for wheels)
solve by matrix or substitution: substitute t in the equations:
2t+2b+4n =378
3t+2b+2n=320
2(144-b-n)+2b+4n=378 ⇒ 288-2b-2n+2b+4n=378
3(144-b-n)+2b+2n=320 ⇒432-3b-3n+2b+2n=320
288-2b-2n+2b+4n=378
432-3b-3n+2b+2n=320
2n=378-288 ⇒ n=90/2=45
-b-n=320-432
-b-45=-112
-b=-112+45 ⇒ b=67
t=144-45-67= 32