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You work for a small business that sells bicycles, tricycles, and tandem bikes Bicycles have one sear, two pedals, and two wheels. Tricycles have one seat, two pedals, and three wheels. Tandem bikes have two seats, four pedals, and two wheels. 1. On Monday you counted 50 tricycle wheels. How many tricycles were in the shop? Write an algebraic equation that shows the relationship between the number of wheels (w) and the number of tricycles (t). 2. On Wednesday there were no tandem bikes in the shop. There were only bicycles, and tricycles. There are a total of 24 seats and 61 wheels in the shop. How many bicycles and how many tricycles are in the shop. Show how you figured it out using algebra. 3. A month later, there are a different number of bicycles, tricycles tandem bikes in the shop. There are a total of 144 front steering handlebars, 378 pedals and 320 wheels. How many bicycles, tricycles, and tandem bikes are in the show? Explain your solution.

Respuesta :

Answer:

Step-by-step explanation:

1- on Monday the number of tricycles: 51/3=17 or 48/3=16 ( can't be 50)

2-the algebraic equation is : t=w/3 ( t=tricycle, w: wheels)

3-On Wednesday: (b for bicycle and t=tricycle)

 2b+3t=61

b+t=24 ⇒ b=24-t

solve by substitution:

2(24-t)+3t=61

48-2t+3t=61

t=61-48 ⇒ t=11

solve for b=24-t

b=24-11=13

t=11, b=13

4)t: tricycles, b for bicycles, n for tandem

t+b+n=144 ( each has one handlebar)⇒ t=144-b-n

2t+2b+4n ( for the pedales)

3t+2b+2n=320 ( for wheels)

solve by matrix or substitution: substitute t in the equations:

2t+2b+4n =378

3t+2b+2n=320

2(144-b-n)+2b+4n=378 ⇒ 288-2b-2n+2b+4n=378

3(144-b-n)+2b+2n=320 ⇒432-3b-3n+2b+2n=320

                                                                                           

288-2b-2n+2b+4n=378

432-3b-3n+2b+2n=320

2n=378-288 ⇒ n=90/2=45

-b-n=320-432

-b-45=-112

-b=-112+45 ⇒ b=67

t=144-45-67= 32

b=67 , tricycle=  32  tandom= 45

( answers in bold )