Answer:
D. 100°
Step-by-step explanation:
Refer to picture attached
Lines QP and QR are tangent to radius of circle.
Triangles ΔQPO and ΔQRO are right triangles and line QO bisects angles of ∠PQR and ∠POR.
So as per sum of angles in right triangle, we have:
- 1/2∠PQR + 1/2∠POR = 90°
- 1/2(81x-1)° + 1/2(100x)° = 90°
- (90.5x)°= 90.5°
- x= 1°
Then:
- mPR(arc)= (100x)°= 100*1°= 100°
Correct answer choice is D. 100°
