The university theater uses a combination of one letter (A - Z) and two digits (0 - 9) to identify their reserved seats. How many reserved seats are
possible using a combination of one letter followed by two digits. EXPLAIN how to solve this problem in your own words.

Respuesta :

Answer:

Hey There!! The answer to this is Correct option: 1) 2600 The letter has a total of 26 possible values (from 'a' to 'z'), and each digit has a total of 10 possible values (from 0 to 9).

So, to find the number of reserved seats possible, we just need to multiply the number of possible values of each letter and digit.

We have one letter and two digits, so we have:

26 * 10 * 10 = 2600 possible reserved seats

Thus, Correct option: 1)

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ItsNobody~ ☆

The total number of combinations of one letter followed by two digits is 2600 option (1) 2600 is correct.

What are permutation and combination?

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

The missing options are:

  • 1.) 2600
  • 2.) 234
  • 3.) 260
  • 4.) 2106

We have:

The university theater uses a combination of one letter (A - Z) and two digits (0 - 9) to identify their reserved seats

As we know, in the alphabet(A to Z) there are the 26 letters and total number of digits (0 to 9) is 10

A total number of combinations of letters followed by two digits can be calculated as follows:

As we have one letter and two digits

= 26×10×10

= 2600

, so we have:

26 * 10 * 10 = 2600 possible reserved seats

Thus, the total number of combinations of one letter followed by two digits is 2600 option (1) 2600 is correct.

Learn more about permutation and combination here:

https://brainly.com/question/2295036

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