Find the first, fourth, and eighth terms of the sequence. A(n) = −5 ∙ 2x − 1

Answer:
Step-by-step explanation:
The rule for the sequence is
[tex]A(n) = 5. {2}^{x - 1} [/tex]
where x is the number of terms
For the first term
x = 1
That's
[tex]A(1) = 5. {2}^{1 - 1} [/tex]
[tex]A(1) = 5. {2}^{0} [/tex]
A(1) = 5(1)
For the fourth term
x = 4
[tex]A(4) = 5. {2}^{4 - 1} [/tex]
[tex]A(4) = 5. {2}^{3} [/tex]
A(4) = 5(8)
For the eighth term
x = 8
[tex]A(8) = 5. {2}^{8 - 1} [/tex]
[tex]A(8 ) = 5. {2}^{7} [/tex]
A(8) = 5(128)
Hope this helps you
Answer:
The first option.
Step-by-step explanation:
The first term of the sequence would be...
A(1) = -5 * 2^(1 - 1)
= -5 * 2^0
= -5 * 1
= -5
The fourth would be...
A(4) = -5 * 2^(4 - 1)
= -5 * 2^3
= -5 * 8
= -40
The eighth would be...
A(8) = -5 * 2^(8 - 1)
= -5 * 2^7
= -5 * 128
= -640
So, the correct answer is the first option.
Hope this helps!