Answer:
Step-by-step explanation:
If the password for a certain safe is indicated by multiplying (x^2-16)/(x-1) with 1 / ((x ^ 2 + 6x + 8) / (x ^ 2 + 2x-3))
Simplify the expression in its lowest term first
[tex]= \dfrac{x^2-16}{x-1} * \dfrac{1}{\dfrac{x ^ 2 + 6x + 8}{x ^ 2 + 2x-3} } \\\\= \dfrac{x^2-16}{x-1} * }{\dfrac{x ^ 2 + 2x - 3}{x ^ 2 + 6x + 8} }\\\\= \dfrac{ (x+4)(x-4)}{x-1} * \dfrac{(x+3)(x-1)}{(x+4)(x+2)}\\\\= \dfrac{x-4}{1} * \dfrac{x+3}{x+2}\\[/tex]
If the value of x = 9, to get the numeric value of the password, we will substitute x = 9 into the resulting function as shown;
[tex]= \dfrac{x-4}{1} * \dfrac{x+3}{x+2}\\\\= \dfrac{9-4}{1} * \dfrac{9+3}{9+2}\\\\= \frac{5}{1} * \frac{12}{11}\\\\= \frac{60}{11}\\ \\= 5.455[/tex]
Hence the numeric value of the password is 5.455
