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How many gram of zinc will have to be treated with dilute hydrochloric acid to liberate 1.85 dm³ of hydrogen at 27°C and 750mmHg?

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kk5996282

Answer:

Explanation:

given

volume=1.85 d m^3

T=27 degree C=27+273 k=300 k

P=750 mmHg

mass of zinc=?

we know that PV=nRT

n=m/M

PV=mRT/M

M for zinc=65.4

PVM=mRT

m=PVM/RT

m=750*1.85*65.4/0.0821*300

m=90742.5/24.63

m=3684

hope this will help u

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