Answer:
JK = 6.86
Step-by-step explanation:
The parameters given are;
LJ = 14
JM = 48
LM = 50
[tex]tan(\angle JML )= \dfrac{Opposite \ leg \ length}{Adjacent \ leg \ length} = \dfrac{LK}{JM} = \dfrac{14}{48} = \dfrac{7}{24}[/tex]
[tex]tan \left( \dfrac{7}{24} \right)= 16.26 ^{\circ }[/tex]
∠JML = 16.26°
Given that ∠JML is bisected by KM, we apply the angle bisector theorem which states that a ray that bisects an interior angle of a triangle bisects the opposite (bisected angle facing side) in the proportion of the ration of the other two sides of the triangle.
From the angle bisector theorem, we have;
LM/JM = LK/JK
50/48 = LK/JK................(1)
LK + KJ = 14.....................(2)
From equation (1), we have;
LK = 25/24×JK
25/24×KJ + JK = 14
JK×(25/24 + 1) = 14
JK × 49/24 = 14
JK = 14×24/49 = 48/7. = 6.86.
JK = 6.86
