Answer:
58
Step-by-step explanation:
Hello, let's note the two digits a and b. the first number 'ab' can be written as 10a +b. For instance if this is 24 it can be written 20 + 4.
If the digits are interchanged the number become 'ba' so 10b + a
We can say that 10a + b + 10b + a = 143
11(a+b)=143
We divide by 13 both sides and we take
a+b = 143/11 = 13
and we know that the digits differ by 3 so b = a + 3
then a + b = a + 3 + a = 2a + 3 = 13
so 2a = 10 and then a = 5
Finally, b = 5+3=8 so the number is 58.
And we can verify that 58 + 85 = 143.
Thanks
Answer:
❍ According to Question now,
➥ 10(x + 3) + x + 10x + x + 3 = 143
➥ 10x + 30 + 12x + 3 = 143
➥ 22x + 33 = 143
➥ 22x = 143 - 33
➥ 22x = 110
➥ x = 110/22
➥ x = 5
Therefore,
The unit digit number = x = 5
The tens digit number = x + 3 = 5 + 3 = 8
The original number = 10(x + 3) + x
The original number = 10(5 + 3) + 5
The original number = 50 + 30 + 5
The original number = 85
Hence,the original number is 85.
