Answer:
(i) (m-3)(2n+m) (ii) (2y+9)(2y-9) (iii) (t-4)(t-2)
Step-by-step explanation:
2mn+m^2-6n-3m
m(2n+m)-3(2n+m)
(m-3)(2n+m)
Answer: (m-3)(2n+m)
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4y^2-81
(2y+9)(2y-9)
Answer: (2y+9)(2y-9)
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t^2-6t+8
(t-4)(t-2)
Factors of the given equations are
(i) (2n +m)(m - 3)
(ii) (2y-9)(2y + 9)
(iii) (t -4) (t - 2)
" Factorization is the process of breaking down large number or quantity into a smaller number or quantity."
Formula used
(a² - b²) = (a -b) (a +b)
According to the question,
(i) 2mn + m² -6n -3m
= m (2n +m) - 3 (2n +m)
= (2n + m) (m - 3)
(ii) 4y² - 81
= (2y)² - (9)²
= (2y - 9) (2y + 9)
(iii) t² - 6t +8
= t² - 4t - 2t + 8
= t (t - 4) -2 (t - 4)
= (t -4) (t -2)
Hence, Factors of the given equations are
(i) (2n +m)(m - 3)
(ii) (2y-9)(2y + 9)
(iii) (t -4) (t - 2)
Learn more about factorization here
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