Answer:
Step-by-step explanation:
[tex]Midpoint = (3,-2)\\1st \: endpoint = (1,6)\\2nd \: endpoint = ?\\\\\\Let \: (1,6) \:be \:x_1y_1\\Let\:(3,-2)\: be\:x\:and\:y\\\\x=(x_1+x_2)/2\\y=\frac{(y_1+y_2)}{2} \\\\3 =\frac{1+x_2}{2} \\\\3\times 2 =1+x_2\\\\6 = 1+x_2\\6-1=x_2\\\\x_2 =5\\\\y=\frac{(y_1+y_2)}{2} \\-2 = \frac{6+y_2}{2}\\\\ -2 \times 2= 6+y_2\\\\-4 = 6+y_2\\\\-4-6=y_2\\\\y_2 = -10\\\\Answer = (5 ,-10)[/tex]
