contestada

For which of the following compound inequalities is there no solution?
A. 3m - 12 > 30 and -6m >= 24
B. -6m >= 12 and m + 5 -18
C. -5m < 20 and 6m > -18
D. -4m - 10 <= -22 and 6m - 8 >= 22
>= is greater than or equal to
<= is less than or equal to

Respuesta :

mirai123

Answer:

A

Step-by-step explanation:

[tex]3m - 12 > 30 \text{ and } -6m\geq 24[/tex]

[tex]\boxed{3m - 12 > 30 \wedge -6m\geq 24}[/tex]

[tex]m>14 \wedge m\leq -4[/tex]

There's no solution. It is the first one already. There is no number that is both greater than 14 and less than or equal to -4. That is no solution because there's no [tex]m[/tex] that satisfy the compound inequality.

Note: the signal change because we divided by negative number.

wegnerkolmp2741o

Answer:

3m - 12 > 30 and -6m >= 24

Step-by-step explanation:

A. 3m - 12 > 30 and -6m >= 24

3m > 42  and m < = -4

m > 14 and m < = -4

This has no solution

B. -6m >= 12 and m + 5 -18

cannot solve since missing inequality

C. -5m < 20 and 6m > -18

m > -4   and m > -3

solution m > -3

D. -4m - 10 <= -22 and 6m - 8 >= 22

-4m < = -12  and 6m > = 30

m > = 3   and m > =5

m > = 5

Otras preguntas