Answer:
Option (1)
Step-by-step explanation:
From the picture attached,
tanθ = [tex]\frac{y}{x}[/tex]
Given : Polar equation as 'θ' = [tex]-\frac{5\pi }{6}[/tex]
Therefore, [tex]\text{tan}(-\frac{5\pi }{6} )[/tex] = [tex]\frac{y}{x}[/tex]
[tex]-\text{tan}(\frac{5\pi }{6} )[/tex] = [tex]\frac{y}{x}[/tex] [Since tan(-θ) = -tanθ]
[tex]\text{tan}(\pi -\frac{5\pi }{6} )[/tex] = [tex]\frac{y}{x}[/tex] [Since -tanθ = tan(π - θ)]
[tex]\text{tan}\frac{\pi }{6}[/tex] = [tex]\frac{y}{x}[/tex]
[tex]\frac{y}{x}=\frac{\sqrt{3}}{3}[/tex]
y = [tex]\frac{\sqrt{3} }{3}x[/tex]
Therefore, y = [tex]\frac{\sqrt{3} }{3}x[/tex] will be the rectangular form of the polar equation.
Option (1) will be the correct option.
