29. A painter leans a ladder against the side of a
house that is 3 feet from the base. If the top
of the ladder reaches 16 feet, how long is the
ladder ?

HELP! answer if you can!​

Respuesta :

Answer:

16.2788 feet

Step-by-step explanation:

a²+b²=c²

3²+16²=c²

9+256=c²

265=c²

c=√265

c=16.2788 feet

If the ladder is 3 feet from the base of the house and the top is 16 feet from the base then the length of ladder is approximately 16.2788 feet long.

What is pythagoras theorem?

Pythagoras theorem says that in a right angled triangle the square of hypotenuse of triangle is equal to the sum of squares of base and perpendicular of that respective triangle.

[tex]H^{2} =P^{2} +B^{2}[/tex] where H is hypotenuse, P is perpendicular, B is base of triangle.

How to find length of ladder?

If a painter leans a ladder against a wall then it forms a right angled triangle so in this we will apply pythagoras theorem to find the length of ladder.

let the length of ladder be h so,

[tex]h^{2} =3^{2} +16^{2}[/tex]

[tex]h^{2} =9+256[/tex]

[tex]h^{2} =265[/tex]

h=[tex]\sqrt{265}[/tex]

h=16.2788 feet.

Hence the length of ladder is 16.2788 feet.

Learn more about pythagoras theorem at https://brainly.com/question/343682

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