Answer:
1) Please find attached the box and whiskers chart created with Excel
2) The conclusions are;
a) The measure of central tendency (the mean and the median) are approximately equal,
b) The standard deviation for the first five data points is 14.17 while the standard deviation for the whole ten data points is 23.99 as such the data values appeared more clustered at the center and show wider spread towards right ends of the chart
Due to the lack of correlation between the standard deviation and the five data values, the data is not uniformly distributed
Step-by-step explanation:
The given data is as follows;
1, 2, 3, 4, 5, 6, 7, 8, 9, 10
15, 18, 22, 32, 50, 50, 55, 56, 81, 81
The first quartile Q₁ = 22
The second quartile, Q₂ (Median) = 50
The third quartile, Q₃ = 56
The interquartile range IQR = 56 - 22 = 34
The minimum value = 15
The maximum value = 81
The mean = 46
The standard deviation = 23.99
Therefore, the measure of central tendency (the mean and the median) are approximately equal,
The data values appeared more clustered at the center and show wider spread towards the left and right ends of the chart
The standard deviation for the first five data points is 14.17 while the standard deviation for the last five data points is
Due to the lack of correlation between the standard deviation and the five data values, the data is not uniformly distributed.
