Answer:
Step-by-step explanation:
Hello, we can write
(1) p(x)=(x-a)q(x)+r
[tex]\boxed{\sf v}[/tex] True
It means that p(a)=0 * q(a) + r = r
so the first one is true.
[tex]\boxed{}[/tex] False
The second one is not to be proven true from the remainder theorem.
[tex]\boxed{\sf v}[/tex] True
For x different from a we can divide the equation (1) by (x-a).
[tex]\boxed{}[/tex] False
We cannot say anything on q(a).
[tex]\boxed{\sf v}[/tex] True
If the rest is 0 then it means that p(a) = 0
[tex]\boxed{\sf v}[/tex] True
If p(a) = 0 it means that the rest r = 0 and then p(x)=q(x)(x-a)
Thank you
