Respuesta :
Answer:
Step-by-step explanation:
x^2 - 17 x + 60
we should find two numbers such that their sum is equal to -17 and product is equal to 60
The two numbers are -12 and -5
now, x^2 - 12 x - 5 x + 60 { splitting the middle term }
x ( x- 12 ) - 5 ( x - 12 )
= ( x - 5 ) ( x - 12 )
hope this helps
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Answer:
x² - 17x + 60 = (x - 12)(x - 5)
Step-by-step explanation:
[tex]x^2-17x+60\quad \implies\quad a=1\,,\quad b=-17\,,\quad c=60\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-(-17)\pm\sqrt{(-17)^2-4\cdot1\cdot60}}{2\cdot1}=\dfrac{17\pm\sqrt{289-240}}{2}=\dfrac{17\pm\sqrt{49}}{2}\\\\x_1=\dfrac{17-7}{2}=5\quad,\qquad x_2=\dfrac{17+7}{2}=12\\\\\\x^2-17x+60=(x-5)(x-12)[/tex]
or:
x² - 17x + 60 =
= x² - 12x - 5x +60 =
= x(x - 12) - 5(x - 12) =
= (x - 12)(x - 5)