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calculate the number of moles equivalent to 25.0 gram of copper II sulfate pentahydrate [CuSO4 5H2O]​

Respuesta :

Stephen46

Answer:

The answer is 0.1 mol

Explanation:

To calculate the number of moles in the given substance we use the equation

[tex]n = \frac{m}{M} [/tex]

where

n is the number of moles

M is the molar mass

m is the mass of the substance

To calculate the number of moles we must first find the molar mass

That's

M( CuSO4 5H2O )

Cu = 64 , S = 32 , O = 16 H = 1

So we have

M( CuSO4 5H2O ) = 64 + 32 + (16 × 4) +

5( 2 + 16)

M( CuSO4 5H2O ) = 96 + 64 + 5(18)

M( CuSO4 5H2O ) = 160 + 90

M( CuSO4 5H2O ) = 250 g/mol

M( CuSO4 5H2O ) = 250 g/mol

mass of CuSO4 5H2O = 25 g

Substitute the values into the above formula

That's

[tex]n = \frac{25g}{250 \: g/mol} [/tex]

We have the final answer as

n = 0.1 mol

Hope this helps you

FadedElla

[tex] \LARGE{ \boxed{ \blue{ \rm{Answer}}}}[/tex]

☃️ Chemical formulae ➝ [tex]\sf{CuSO_4.5H_2O}[/tex]

How to find?

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

[tex] \boxed{ \sf{No. \: of \: moles = \frac{Given \: weight}{Molecular \: weight} }}[/tex]

Solution:

Atomic weight of Elements:

  • Cu = 64
  • S = 32
  • O = 16
  • H = 1

❍ Molecular weight of [tex]\sf{CuSO_4.5H_2O}[/tex]

= 64 + 32 + (16 × 4) + 5(2 × 16)

= 96 + 64 + 90

= 250 g/mol

❍ Given weight: 25 g

Then, no. of moles,

⇛ No. of moles = 25 g/ 250 g mol‐¹

⇛ No. of moles = 0.1 moles

⚘ No. of moles of Copper Sulphate pentahydrate in the given weight = 0.1 moles.

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