Answer:
d=5√2 unit
Step-by-step explanation:
distance between two points d=√(x2-x1)²+(y2-y1)²
two pints (-3,-4) and (4,-5)
d=√(4-(-3)²+(-5-(-4)²
d=√(4+3)²+(-5+4)²
d=√49+1
d=√50
d=√25*2
d=5√2
Answer
[tex] \boxed{5 \sqrt{2} \: \: \:units}[/tex]
Step by step explanation
Let the points be A and B
A ( - 3 , - 4 ) ⇒( x₁ , y₁ )
B ( 4 , - 5 )⇒( x₂ , y₂ )
Now, let's find the distance between these points :
Distance = [tex] \mathsf{ \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }[/tex]
Plug the values
⇒[tex] \mathsf{ \sqrt{ {(4 - ( - 3))}^{2} + {( - 5 - ( - 4))}^{2} } }[/tex]
Calculate
⇒[tex] \mathsf{ \sqrt{ {(4 + 3)}^{2} + {( - 5 + 4)}^{2} } }[/tex]
⇒[tex] \mathsf{ \sqrt{ {(7)}^{2} + {( - 1)}^{2} } }[/tex]
Evaluate the power
⇒[tex] \mathsf{ \sqrt{49 + 1} }[/tex]
Add the numbers
⇒[tex] \mathsf{ \sqrt{50} }[/tex]
Simplify the radical expression
⇒[tex] \mathsf{5 \sqrt{2} \: \: units}[/tex]
Hope I helped!
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