Answer:
The answer is option B
Step-by-step explanation:
To find the side adjacent to the 50° angle we use tan
[tex] \tan( \alpha ) = \frac{opposite}{adjacent} [/tex]
From the question
The opposite is 6m
The adjacent is ?
So we have
[tex] \tan(50) = \frac{6}{?} [/tex]
[tex]? \tan(50) = 6[/tex]
[tex]? = 6 \times \frac{1}{ \tan(50) } [/tex]
But
[tex] \frac{1}{ \tan(x) } = \cot(x) [/tex]
So we have
[tex] \frac{1}{ \tan(50) } = \cot(50) [/tex]
Substitute it into the expression
That's
We have the final answer as
[tex]? = 6 \cot(50) [/tex]
Hope this helps you
