Respuesta :

Answer:

x ≤ [tex]\frac{9}{5}[/tex]

Step-by-step explanation:

Given

[tex]\frac{1}{4}[/tex](12x + 8) ≤ - 2x + 11 ← distribute parenthesis on left side

3x + 2 ≤ - 2x + 11 ( add 2x to both sides )

5x + 2 ≤ 11 ( subtract 2 from both sides )

5x ≤ 9 ( divide both sides by 5 )

x ≤ [tex]\frac{9}{5}[/tex]

Swizkhidd

Answer:

x≤ 3/-10

Explanation:

Firstly given that

-¼(12x+8) ≤ -2x+11

• Divide by 4

4X-¼(12x+8) ≤-2x+11

= -12x + 8 ≤ -2x + 11

• Group like terms

-12x + 2x ≤ 11 - 8

= -10x/10 ≤ 3/-10

x≤ 3/-10

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