Respuesta :

The can be divided into two rectangles, one having length [tex]8.3[/tex] and width $3.8$

Another with, dimensions $7.4-3.8=3.6$ and $3.9$

Area of first rectangle=$3.8\times8.3=31.54$

Area of second rectangle =$3.6\times3.9=14.04$

Total area $=31.54+14.04=45.58$ ft²

wegnerkolmp2741o

Answer:

45.58 ft^2

Step-by-step explanation:

We can split the figure into two pieces

We have a tall rectangle that is 3.8 by 8.3

A = 3.8 * 8.3 =31.54 ft^2

We also have a small rectangle on the right

The dimensions are ( 7.4 - 3.8) by 3.9

A = 3.6*3.9 =14.04 ft^2

Add the areas together

31.54+14.04

45.58 ft^2

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