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35.
What is the equation of the line that is
parallel to y = 4x + 3 and passes through
the point (2,6)?

HELP! answer if you can!​

Respuesta :

leena

Hi there! :)

Answer:

[tex]\huge\boxed{y = 4x - 2}[/tex]

Given line with an equation of y = 4x + 3

Parallel lines contain equivalent slopes, so a parallel line to the given equation would contain a slope of m = 4.

Plug in the coordinates of the point given, along with the slope into the equation y = mx + b where:

m = slope

y = y-coordinate of point

x = x-coordinate of point

Solve for the 'b' value, or y-intercept:

y = mx + b

6 = 4(2) + b

6 = 8 + b

b = -2

Rewrite the equation as slope-intercept form:

y = 4x - 2

Answer:

When you see the word "parallel", you know the new line will have the same slope.

parallel to y = 4x + 3

So, the new line will have a slope of 4

"Indicate the region where y≥ 4x + 3

Plot y= 4x + 3 by finding the points that make it true. For example, (y = 0, x = 3/4), (y = 2, x = 2) and so on.

y = 4x + b

b is the y intercept ( point y when x = 0)

Insert new coefficients:

+2 = 4(0) + b

b = +2

y = 4 + 2

[tex] \: [/tex]

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