Answer:
The answer is option D
Step-by-step explanation:
[tex]( { \frac{ {x}^{ - 6} }{ {x}^{2} } })^{3} [/tex]
Using the rules of indices multiply the terms
That's
[tex]( { {a}^{x} })^{y} = {a}^{x \times y} [/tex]
Applying the same rule we have
[tex] \frac{ {x}^{ - 6 \times 3} }{ {x}^{2 \times 3} } = \frac{ {x}^{ - 18} }{ {x}^{6} } [/tex]
Using the rules of indices since they are dividing we subtract the exponents
That's
[tex] {x}^{ - 18 - 6} = {x}^{ - 24} [/tex]
And
[tex] {x}^{ - y} = \frac{1}{ {x}^{y} } [/tex]
So we have the final answer as
[tex] \frac{1}{ {x}^{24} } [/tex]
Hope this helps you
