Write the equation of the line that is parallel to the line y=−14x−3 through the point (4,4). A. y=x+5 B. y=−14x+5 C. y=5x+1 D. y=5x−14

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Answer:

None of the answers seem to be correct.

Step-by-step explanation:

The given equation is of the form y = mx + b where m is the slope and b is the y-intercept.

Here, m = -14

Two parallel lines have the same slope. So, the slope of the new line will be -14.

To calculate the y-intercept substitute x=4 and y=4 in the equation.

4 = (-14)(4) + b

Solving for b, we get b = 60.

So, the new equation will be y = -14x + 60

The equation of the line parallel to the given line is y =-14x+60, none of the given options is correct.

What is the equation of a straight line ?

The equation of the straight line is given by y = mx +c , Where m is the slope of the line and c is the y-intercept.

The equation of the line is y = -14x -3

The slope of the line parallel to this will be the same as the given line.

m = -14 for both the lines

The line equation parallel to the given line is

y = -14x +c

The line passes through the points (4,4)

4 = -14 * 4 + c

c = 60

y = -14x +60

Therefore, the equation of the line parallel to the given line is y =-14x+60.

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