Answer:
a.0.375
b.0.125
c.0.375
1.0.375
2.0.125
3.0.375
Step-by-step explanation:
a.
The total events in a sample space are n(S)=8
The events that contains exactly two boys
Boy Boy Girl,Boy Girl Boy,Girl Boy Boy.
Let A be the event that there are exactly two boys. Thus, n(A)=3.
So, probability of exactly 2 boys is P(A)=n(A)/n(S)=3/8=0.375.
b.
The event that contains exactly 0 girls.
Boy Boy Boy
Let B be the event that contains exactly 0 girls. Thus, n(B)=1.
So, probability of exactly 0 girls is
P(B)=n(B)/n(S)=1/8=0.125.
c.
The events that contains exactly 1 girl.
Boy Boy Girl,Boy Girl Boy,Girl Boy Boy
Let C be the event that contains exactly 1 girl. Thus, n(C)=3.
So, probability of exactly 1 girl is
P(C)=n(C)/n(S)=3/8=0.375.
Q1 is same as part a.
Q2 is same as part b.
Q3. is same as part c
