Answer: -1
Step-by-step explanation:
The given function : [tex]f(p) = p^2 + 3p + 1[/tex]
To find : The value of the given function ( [tex]f(p) = p^2 + 3p + 1[/tex]) at p =-2.
We substitute the value of p=-2 in the given function, we get
[tex]f(-2) = (-2)^2 + 3(-2) + 1\\\\\Rightarrow\ f(-2)=4-6+1\\\\\Rightarrow\ f(-2)=-2+1\\\\\Rightarrow\ f(-2)=-1[/tex]
Therefore , the value of the given function at p=-2 = -1
