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what is the volume of a sample of helium that has a mass of 6 × 10−3 g, and a density of 0.17847 g/l? answer in units of ml

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[tex]d=0,17847\frac{g}{L}=0,17847\frac{g}{1000mL}=1,7847*10^{-4}\frac{g}{mL}\\\\ m = 6*10^{-3}g\\\\\\ V=\frac{m}{d}=\frac{6*10^{-3}g}{1,7847*10^{-4}\frac{g}{mL}}\approx3,362*10^1L=33,62mL[/tex]

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