Respuesta :
mass of oxygen = 230g - (136,6g + 26,4g + 31,8g) = 35,2g
If 230g ---- is ----- 100%
so
35,2g ---- is ------ %O
%O = (35,2g*100%) / 230g = 15,3%
If 230g ---- is ----- 100%
so
35,2g ---- is ------ %O
%O = (35,2g*100%) / 230g = 15,3%
Answer: The mass percent of oxygen in given compound is 15.30%.
Explanation:
We are given:
Mass of nitrogen in compound = 31.8 g
Mass of hydrogen in compound = 26.4 g
Mass of carbon in compound = 136.6 g
Total mass of compound = 230 g
So, mass of oxygen will be = [tex]230-(136.6+26.4+31.8)=35.2g[/tex]
To calculate the percentage composition of element in a compound, we use the following equation:
[tex]\% \text{composition}=\frac{\text{Mass of the element}}{\text{Mass of the compound}}\times 100[/tex]
Putting values in above equation, we get:
[tex]\% \text{composition of oxygen}=\frac{35.2g}{230g}\times 100=15.30\%[/tex]
Hence, the mass percent of oxygen in given compound is 15.30%.