Hello,
[tex]ax^2+5x+b=a(x^2+ \frac{5}{a}*x+ \frac{b}{a})\\
=k(x-3)(x- \frac{1}{3})\\
=k(x^2-3x- \frac{1}{3}*x+1)\\
=k(x^2- \frac{10}{3}*x+1)\\
x^2--\ \textgreater \ k=a\\
x--\ \textgreater \ 5=-a* \frac{10}{3} ==\ \textgreater \ a=- \frac{3}{2} \\
x^0--\ \textgreater \ b=a[/tex]