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A 32​-inch piece of steel is cut into three pieces so that the second piece is twice as long as the first​ piece, and the third piece is two times more than seven times the length of the first piece. Find the lengths of the pieces.

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tesspueschel

Answer:

first piece = 1.88in

second piece= 3.76in

third piece = 26.32in

32 = f + s + t

1st piece = f

2nd piece = s

3rd piece = t

what we know:

s = 2f

t = 2(7f)

32 = f + 2f + 2(7f)

32 = 3f +14f

32 = 17f

f = 1.88

now sub in:

f = 1.88

s = 3.76

t = 26.32

when you add these together you get 31.96, when you round up you get 32 which is the original piece of steel.