Answer:
mAngleB= 50
mAngleC= 130
Explanation:
Complementary angles = 90
So If angle A is 40 subtract that to 90 to find angle B which is 50
and 50+40= 90 = Complementary
Supplementary angles = 180
So if angle C is supplementary to angle B you would need to subtract 50 from 180 to find angle C which is 130
130+20= 180 = supplementary
The measure of [tex]\angle B[/tex] is [tex]50^o[/tex] while that of [tex]\angle C[/tex] is [tex]130^o[/tex].
Given that:
[tex]\angle A=40^o[/tex]
To find:
[tex]\angle B[/tex] and [tex]\angle C[/tex]
Since, [tex]\angle B[/tex] is the complement of [tex]\angle A[/tex], which is equal to [tex]90^o[/tex].
Equation for complementary angle becomes:
[tex]\angle A+\angle B=90^o[/tex]
Put the value in above equation:
[tex]\angle B=90^o-40^o\\\\\angle B=50^o[/tex]
Also, [tex]\angle C[/tex] is the supplement of [tex]\angle B[/tex], which is equal to [tex]180^o[/tex].
Equation for supplementary angle becomes:
[tex]\angle B+\angle C=180^o[/tex]
Put the value in above equation:
[tex]\angle C=180^o-50^o\\\\\angle C=130^o[/tex]
So, [tex]\angle B[/tex] is equal to [tex]50^o[/tex] and [tex]\angle C[/tex] is equal to [tex]130^o[/tex].
Learn more about complementary and supplementary angles: https://brainly.com/question/2882938
