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Two 1.9 kg masses are 1.1 m apart (center to center) on a frictionless table. Each has + 9.6 μC of charge.
What is the magnitude of the electric force on one of the masses?

Respuesta :

Answer:

F= 0.6 N

Explanation:

Fe(electrical force)=[tex]k q1q2/r^2[/tex]

    [tex]k=9*10^9\\q1=-9.6 *10^-6 C\\q2= -9.6*10^-6 C\\r= 1.1m[/tex]

So,    

        [tex]F=\frac{9*10^9*-9.6 *10^-6 C* -9.6*10^-6 C}{1.1^2}[/tex]

         [tex]F= 0.6 N[/tex]

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