& Difference between heats of san at const pressure
and constant volume for ran.
2 Calc() + 150, 13)
12 CO2+ GH20W at 25°C
moving
1. with
centri
KI
LS
- 7.43
„S:
ť 8.72
-3.72
+9.43​

Respuesta :

Answer:

The statement is not written clearly, so possible answer is 7.43KJ .

Explanation:

  • The heat of reaction is basically ΔH at constant pressure and is ΔU at constant volume.
  • Since, for any reaction the relation between this heats is given by equation,

                           ΔH = ΔU + (Δng  )RT

       where,

                  Δng = change in number of gaseous moles in any reaction.

  • Since, in the above reaction the only gaseous species are CO2

​ and O2 , so,

              Δng  =12−15=−3.

  • Hence, using ΔH - ΔU = (Δng )RT

                           ΔH - ΔU =(−3)RT=(−3)×8.314×298.15J      (T in Kelvin)

                           =>  ΔH - ΔU=7430J=7.43KJ