Respuesta :

Answer:

3.011 x 10^23 molecules

Explanation:

  • Mass of Sulphuric (H2SO4) = 49g
  • We have the number of molecules in 49g of H2SO4

Molecular mass of H2SO4 = (Atomic mass of H) x 2 + (Atomic mass of S) x 1 + (Atomic mass of O) x 4

                                            = ( 1 x 2) + (32 x 1) + (16 x 4)

                                             = 2 + 32 + 64

                                            = 98.

Now,

  •      According to the formula,

Number of moles in the given H2SO4(n)  = Mass of H2SO4 in grams/Molecular mass of H2SO4

                                         = 49/98

                                          = 1/2

                                          = 0.5

                                     : n = 0.5 mol

  • 1 mol of H2SO4 contains 6.022 x 10^23 molecules.
  • 0.5 mol of H2SO4 contains 0.5 x 6.022 x 10^23 molecules.

                                    = 3.011 x 10^23 molecules .

that is 49 g of H2SO4 contains 3.011 x 10^23 molecules of H2SO4.

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