Answer:
Explanation:
Given the following :
Horizontal distance = distance from base of the wall = 5m
Vertical distance = - 4.5m
Acceleration due to gravity g = 0 (horizontal motion) g = 9.8m/s² (vertical motion)
To obtain time :
From S = 0.5 at²
-4.5 = 0.5 × 9.8 × t²
-4. 5 = 4.9t²
-4.5 / 4.9 = t²
- 0.9183673 = t²
t = 0.9583148
Hence, horizontal Velocity = distance / time
Vx = 5 / 0.9583148
= 5.2174919 m/s
The speed at which the pebbles are going when they hit the window is gotten as;
v_h = 5.21 m/s
We are given;
Vertical displacement; h = 4.5 m
Horizontal displacement; d = 5 m
Now, know the pebbles are thrown such that they have only a horizontal component of velocity when they strike the window. Thus, the final vertical component(v) of the velocity of the pebble when it hits the window must be equal to zero.
Thus; v = 0 m/s
Let's Calculate the initial vertical component of the velocity from;
v² = u² + 2gh
0 = u² + 2(-9.8 × 4.5)
u² = 88.2
u = √(88.2)
u = 9.3915 m/s
Now, let us find the time from;
v = u + gt
0 = 9.3915 - 9.8t
t = 9.3915/9.8
t = 0.9583 s
Thus, speed at which the pebbles are going when they hit the window is;
v_h = d/t
v_h = 5/0.9589
v_h = 5.21 m/s
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