(II) The pressure in an ideal gas is cut in half slowly, while
being kept in a container with rigid walls. In the process,
465 kJ of heat left the gas. (a) How much work was done
during this process? (b) What was the change in internal
energy of the gas during this process?

As per the concepts and fundamentals of thermodynamics, whenever there is some heat absorption or heat release from the system, then the volume of gas inside the system changes, this change is determined by the work done during a thermodynamic process. So, the expression for the work done is given as,

W = PV

here, P is the pressure and V is the Volume.

(a)

Since, there is no change in volume , which means V = 0.

Hence, the work done is,

W = P (0)

W = 0

Thus, we can conclude that the work done during the given process is zero.

(b)

Applying the first law of thermodynamics as,

Q = U + W

Here, U is the Change in internal energy. Solving as,

- 465 kJ = U + 0

Negative shows that the heat is leaving from the system. So,

U = - 465 kJ.

Thus, we can conclude that the required change in internal energy is -465 kJ.

Learn more about the first law of thermodynamics here:

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(II) The pressure in an ideal gas is cut in half slowly, while being kept in a container with rigid walls. In the process, 465 kJ of heat left the gas. (a) How much work was done during this process? (b) What was the change in internal energy of the gas during this process?

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(II) The pressure in an ideal gas is cut in half slowly, while
being kept in a container with rigid walls. In the process,
465 kJ of heat left the gas. (a) How much work was done
during this process? (b) What was the change in internal
energy of the gas during this process?