[tex]\boxed{ \bf{Given : }}[/tex]
[tex] \boxed{ \bf{To \: be \: calculated : }}[/tex]
From what height was the ball bearing dropped?
[tex] \boxed{ \bf{Solution : }}[/tex]
By using second equation for freely falling body, we get:
[tex] \sf{h = ut + \frac{1}{2} gt {}^{2} }[/tex]
Substituting the values..
[tex] \sf\rightarrow \: h = 0 \times 20.9 + \dfrac{1}{ \cancel{2}} \times \cancel{9.8} \times 20.9[/tex]
[tex] \sf \rightarrow \: h = 0 + 4.9 \times 20.9[/tex]
[tex] \sf \rightarrow \: 102.41 \: m \: (approx)[/tex]
[tex] \bf \therefore \: Height \: is \: 102.41 \: m[/tex]
