Respuesta :
Given :
Height from which ball is dropped , h = 40 m .
Acceleration due to gravity , g= 10 m/s² .
Initial velocity , u = 0 m/s .
To Find :
Velocity when ball covered 20 m and velocity when it hit the ground .
Solution :
Now , height when ball covered 20 m distance is , 40 - 20 = 20 m .
By equation of motion :
[tex]v^2=u^2+2gh\\\\v=\sqrt{2\times 10\times 20}\ m/s\\\\v=20\ m/s[/tex]
Now , distance covered when body reaches ground is , 40 m .
Putting value h = 40 m in above equation , we get :
[tex]v=\sqrt{2\times 10\times 40}\ m/s\\\\v=20\sqrt{2}\ m/s[/tex]
Hence , this is the required solution .
